connor02 said:The Attempt at a Solution
So i have
E=(-1k/r^2)+(3k/(1+r)^2)
connor02 said:Setting E=0
1k/r^2=3k/(1+r)^2
r= sqrt(0.5) = 0.707
is this correct?
No, it isn't. Your r is clearly a number, not a point. I suspect you mean it is the x-coordinate of such a point. In that case, the distance to 0 is r but the distance to 1 is |1- r| not 1+ r.connor02 said:r=the point on the x-axis where the E firld is 0
right?
connor02 said:my bad. r=distance to the right of the -1C charge. x=1.707 is the point on the x-axis where E=0.
right?
When the electric field is 0 at a point on the x axis, it means that there is no net flow of electric charge in that direction. This can occur if there are equal and opposite charges on either side of the point, canceling out the electric field.
To determine the point on the x axis where the electric field is 0, we can use the equation E = kq/r^2, where E is the electric field, k is the Coulomb's constant, q is the electric charge, and r is the distance from the charge. We can set E equal to 0 and solve for r to find the distance from the charge where the electric field is 0.
Yes, the electric field can be 0 at multiple points on the x axis. This occurs when there are multiple charges with equal and opposite values located at different distances from the point on the x axis.
The electric field being 0 at a point on the x axis indicates that there is no force acting on a charged particle placed at that point. This can be useful in understanding the behavior of charged particles in an electric field.
No, the electric field cannot be 0 at a point on the x axis if there is a non-zero charge located at that point. This is because the electric field is a measure of the force that a charge would experience at that point, and a non-zero charge would create a non-zero electric field at that location.