# Electric Field and Magnetic Field

## Homework Statement

A 6.45 uC particle moves through a region of space where an electric field of magnitude 1220 N/C points in the positive direction, and a magnetic field of magnitude 1.19 T points in the positive z direction. If the net force acting on the particle is 6.45E-3 N in the positive direction, calculate the magnitude of the particle's velocity. Assume the particle's velocity is in the x-y plane.

F=qE
v=1/B(E-Fnet/q)

## The Attempt at a Solution

This is what I did:
using F=qE: (6.45 e-6 C)(1220N/C)= 0.00787 N

Then using V=...
: (1/1.19T)(1220N/C - 6.45 E-3/6.45 e-6)= 184.8 m/s

BUT it keeps telling me my answer is wrong... do I have to put it in the negative direction?

Related Introductory Physics Homework Help News on Phys.org
Where does your second equation come from? If we let the "positive direction" be the x-direction, which direction is the velocity pointing in?

The velocity will point in the negative Y direction according to the right hand rule.

The equation comes from:

netForce= qE-qvB

And when you plug all the values in i keep getting: 184.8 m/s but my computer says it is wrong.