Electric field and speed - find acceleration.

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SUMMARY

A proton accelerates from rest in a uniform electric field of 640 N/C, achieving a speed of 1.20 x 10^6 m/s. The acceleration can be calculated using Newton's second law, F = ma, where the force is derived from the electric field. The time taken to reach this speed and the distance traveled can be determined using kinematic equations. The kinetic energy at the final speed can be calculated using the formula KE = 0.5 * m * v^2, where m is the mass of the proton.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of electric fields and forces (E = F/q)
  • Familiarity with kinematic equations for motion
  • Basic concepts of kinetic energy (KE = 0.5 * m * v^2)
NEXT STEPS
  • Calculate the acceleration of a proton in an electric field using F = ma
  • Explore kinematic equations to determine time and distance traveled
  • Learn how to calculate kinetic energy for charged particles
  • Investigate the relationship between electric fields and forces on charged particles
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism and kinematics, as well as educators seeking to clarify concepts related to electric fields and particle motion.

Mommy2KAR420
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Homework Statement


A proton accelerates from rest in a uniform electric field of 640N/C. At some later time, its speed is 1.20x10^6m/s.
a) Find the magnitude of the acceleration of the proton.
b) How long does it take the proton to reach this speed?
c) How far has it moved in that interval?
d) What is its kinetic energy at the later time?


Homework Equations





The Attempt at a Solution


I think I can figure this problem out after knowing how to get started. I was confused as to how to start without having the mass. Any help?
 
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You can look up the mass and charge of a proton.
Use F = ma.
Of course it is the electric field that causes the force, so put in the formula for that.
 
Thank you. I went outside for a break and had the revelation. I feel stupid now. I got the answer for each part now. I don't know why I wasn't thinking about looking up the charge and mass. Thanks again!
 

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