Electric Field Between/Above Parallel Charged Rods

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SUMMARY

The discussion focuses on calculating the electric field between and above two infinitely long parallel charged rods, each with linear charge densities of +λ and -λ. The electric field (E) between the rods is derived using the formula E = qL/(πεd), where q is the charge, L is the length, ε is the permittivity, and d is the distance between the rods. It is confirmed that the electric field above the rods is not zero, contrary to initial assumptions, and the calculation involves taking the vector sum of the fields from both rods.

PREREQUISITES
  • Understanding of electric fields and charge distributions
  • Familiarity with the concept of linear charge density
  • Knowledge of calculus for integrating electric field equations
  • Basic principles of electrostatics, particularly for infinite charged rods
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  • Study the electric field of an infinite line charge using the formula E = (1/4πε₀)(2λ/r)
  • Explore vector addition of electric fields from multiple charge distributions
  • Investigate the behavior of electric fields at large distances from charged objects
  • Learn about the applications of Gauss's Law in calculating electric fields
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Students studying electromagnetism, physics educators, and anyone interested in understanding electric fields generated by charged rods.

Fusilli_Jerry89
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Homework Statement


2 uniformly charged very long (L -> infinite) straight, parallel rods d cm apart each carry a linear charge density +lambda and -lambda.
Find the magnitude and direction of the electric field between the 2 rods (x=0, -d/2 < z < d/2) and above the rods (x=0, z > d/2)


________________________________

---------------------------------------------->x
________________________________ (z is vertical axis)

Homework Equations



E = q/4(pi)(epsilon)(r^2)

The Attempt at a Solution


First of all, would E be zero above the 2 rods? The question also has a b part to it that asks what the behavior is if z is much greater than d. I guessed that E was not zero above the 2 rods since it seemed like there were so many marks for finding E above the rods, but was I wrong? If not, do you calculate E above the rods the pretty much the same way as below only subtract them instead of add them?

For E between the rods:
dE = q/4(pi)(epsilon)(x^2 + (d^2)/4)
cos(theta) = (d/2)/(x^2 + (d^2)/4)^.5
dEz = qd/8(pi)(epsilon)(x^2 + (d^2)/4)^3/2

Ez = [qd/8(pi)(epsilon)] * integral from -L/2 to L/2 of (x^2 + (d^2)/4)^-3/2 dx
Ez = qL/2(pi)(epsilon)d
since there are two rods, we multiply this by 2:
E = qL/(pi)(epsilon)d

is this method/approach correct? Thx
 
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Fusilli_Jerry89 said:

The Attempt at a Solution


First of all, would E be zero above the 2 rods? The question also has a b part to it that asks what the behavior is if z is much greater than d. I guessed that E was not zero above the 2 rods since it seemed like there were so many marks for finding E above the rods, but was I wrong? If not, do you calculate E above the rods the pretty much the same way as below only subtract them instead of add them?

E would not be zero above the rods -- that happens with infinite planes.

You have to know the field of an infinite wire at a dist r. This is done in all the books, so I'll just give it here:

[tex]\frac{1}{4\pi\epsilon_{0}} \frac{2\lambda}{r}.[/tex]

The direction of the field is obvious.

You have to take the vector sum of the fields due to the two rods. In this case, since both the fields are in the same line, just adding or subtracting will do. To find it at a large distance, take the limit of z tending to infinity.

If you look at the two rods from a great distance, how do you feel it should look like?
 

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