Electric Field Between Oppositely Charged Parallel Plates

  • #1

Homework Statement



An infinite plane of charge with surface charge density sigma = 8.00 nC/m^2 lies in the yz plane at the origin, and a second infinite plane of charge with surface charge density sigma = -8.00 nC/m^2 lies in a plane parallel to the yz plane at x = 4.00 m. The electric field at x = 3.50 m is approximately



a.226 N/C
b.339 N/C
c.904 N/C
d.452 N/C
e.zero



Homework Equations



E = sigma/epsilon_0 for oppositely charged parallel plates

The Attempt at a Solution


E = sigma/epsilon_0 = (8.00*10^-9 C/m^2)/(8.85*10^-12) = 904 N/C ?


Homework Statement



An infinite plane of charge with surface charge density sigma = 8.00 nC/m^2 lies in the yz plane at the origin, and a second infinite plane of charge with surface charge density sigma = -8.00 nC/m^2 lies in a plane parallel to the yz plane at x = 4.00 m. The electric field at x = 5.00 m is approximately

a.226 N/C
b.339 N/C
c.904 N/C
d.452 N/C
e.zero


Homework Equations



See below.

The Attempt at a Solution



If one draws a diagram for the E (and F) vectors, the vectors cancel each other out when outside the space between the plates, so it is 0?

Thanks.
 
  • #2
It's all good. (I didn't check your arithmetic for the first one, but your method is correct.)
 

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