Electric Field due to Solid Non-Conducting Cylinder

In summary, the task is to find the electric field intensity, E, as a function of radius outside a solid non-conducting cylinder with positive charge distributed throughout. The charge density increases with radius and is represented by ρ = {ρ}_{o}({r}{^2}/{b}{^2}), where {ρ}_{o} is a constant. This can be solved using Gauss's Law, as shown in similar examples and resources provided.
  • #1
thiefjack
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0

Homework Statement



Positive charge is distributed throughout a solid non-conducting cylinder of radius 'b ' and infinite length. The charge density increases with radius according to ρ = [itex]{ρ}_{o}[/itex]([itex]{r}{^2}/{b}{^2}[/itex]), where [itex]{ρ}_{o}[/itex] is a constant (evidently equal to the charge density at the surface of the cylinder).

Find the electric field intensity, E, as a function of radius, outside the cylinder.

Homework Equations



E = k[itex]{dq}/{r}^{2}[/itex]

The Attempt at a Solution



Not sure where to get started, actually. If we try to find the electric field intensity at a position outside the cylinder wouldn't it be dependent on how far out we're finding the electric field and not dependent on the radius?
 
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  • #2
This is a straight forward application of Gauss's Law. See example 1.4 which is similar to your problem.

http://ecee.colorado.edu/~bart/book/book/chapter1/ch1_3.htm

See also,

http://www.chem.ox.ac.uk/teaching/Physics%20for%20CHemists/Electricity/Gauss.html

http://research.physics.illinois.edu/PER/unit4.pdf
 
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  • #3
I got the right answer with your help, Spinnor.

Thanks for the pointing me in the right direction.
 

What is the formula for calculating the electric field due to a solid non-conducting cylinder?

The formula for calculating the electric field due to a solid non-conducting cylinder is: E = (λ/2πε0)(1/r - 1/R), where λ is the linear charge density, ε0 is the permittivity of free space, r is the distance from the center of the cylinder, and R is the radius of the cylinder.

How does the electric field vary with distance from the center of a solid non-conducting cylinder?

The electric field due to a solid non-conducting cylinder varies inversely with the distance from the center of the cylinder. This means that as the distance increases, the electric field decreases.

What is the direction of the electric field due to a solid non-conducting cylinder?

The electric field due to a solid non-conducting cylinder is directed radially inward or outward, depending on the charge distribution. If the cylinder has a positive charge, the electric field will be directed outward, and if it has a negative charge, the electric field will be directed inward.

Can the electric field due to a solid non-conducting cylinder be zero?

Yes, the electric field due to a solid non-conducting cylinder can be zero at certain points. This occurs when the linear charge density is zero or when the distance from the center of the cylinder is equal to the radius of the cylinder.

How does the electric field due to a solid non-conducting cylinder compare to that of a solid conducting cylinder?

The electric field due to a solid non-conducting cylinder is stronger at a given distance from the center compared to that of a solid conducting cylinder with the same charge and dimensions. This is because a solid conducting cylinder redistributes its charge on the surface, while a non-conducting cylinder maintains its charge distribution along its entire length, resulting in a stronger electric field.

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