Electric Field due to Solid Non-Conducting Cylinder

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SUMMARY

The discussion focuses on calculating the electric field intensity, E, outside a solid non-conducting cylinder with a radius 'b' and a charge density defined by ρ = ρ₀(r²/b²). The solution utilizes Gauss's Law, confirming that the electric field intensity depends on the distance from the cylinder rather than the radius itself. Participants referenced specific resources, including example problems and educational materials, to clarify the application of Gauss's Law in this context.

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Homework Statement



Positive charge is distributed throughout a solid non-conducting cylinder of radius 'b ' and infinite length. The charge density increases with radius according to ρ = {ρ}_{o}({r}{^2}/{b}{^2}), where {ρ}_{o} is a constant (evidently equal to the charge density at the surface of the cylinder).

Find the electric field intensity, E, as a function of radius, outside the cylinder.

Homework Equations



E = k{dq}/{r}^{2}

The Attempt at a Solution



Not sure where to get started, actually. If we try to find the electric field intensity at a position outside the cylinder wouldn't it be dependent on how far out we're finding the electric field and not dependent on the radius?
 
Last edited:
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This is a straight forward application of Gauss's Law. See example 1.4 which is similar to your problem.

http://ecee.colorado.edu/~bart/book/book/chapter1/ch1_3.htm

See also,

http://www.chem.ox.ac.uk/teaching/Physics%20for%20CHemists/Electricity/Gauss.html

http://research.physics.illinois.edu/PER/unit4.pdf
 
Last edited by a moderator:
I got the right answer with your help, Spinnor.

Thanks for the pointing me in the right direction.
 

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