# Electric field in the narrow wire

DottZakapa
Homework Statement:
A narrow copper wire of length L and radius b is attached to a wide copper wire of length L and radius 2b, forming one long wire of length 2L. This long wire is attached to a battery, and a current is flowing through it. If the electric field in the narrow wire is E, the electric field in the wide wire is
Relevant Equations:
current
i've started from this I1=I2
then
I1= JA1=##\frac {E l} R##

I2= JA2=##\frac {E_2 l} R##

but can't get anything useful relating them. Am i forgetting any other useful formula?
I get as result E4

Homework Helper
Gold Member
Why are you using the same J in the two equations? If the current is the same in the two wires would the current density also be the same? Also the wires don't have the same resistance.

DottZakapa
Why are you using the same J in the two equations? If the current is the same in the two wires would the current density also be the same? Also the wires don't have the same resistance.
you right
##I_1= J A## , ##A_2 = pi 4b^2##
##I_2=J_2 A_2##
##j_2= \frac j 4 ##
then ?
##I_2 = \frac j 4 \ A_2 = \frac {E l} {R}\space but\space then \space A_2\space simplify\space with\space the\space 4\space and \space i\space get\space back\space to\space the\space beginning...##
sorry I'm not getting anywhere • • 