- #1

LCSphysicist

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- Homework Statement
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- Relevant Equations
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Hello. I am having some trouble to understand the resolution of this question.

We could easily try to calculate the electric field relative resultant at the screen. The problem i am having is about the amplitude of the electric field:

Generally, we have that the intensity part dependent of the width of the slits is $$I = C(\frac{sin \beta}{\beta})^2$$, where ##\beta = \pi w_i \theta / 2##, so that ##|E| = C' \sqrt{I} = C'' / w_i##, that is, the ampltitude of E is inverselly proportional to w. This would imply that the ##w_2## slit produce a electric field with amplitude weaker than the other one, in fact, $$|E_1|/|E_2|= 2$$.

BUT, the solution says that ##|E_2|/|E_1| = 2##, so where am i wrong?