Electric field inside a cavity within a sphere

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SUMMARY

The electric field inside a spherical cavity within a larger sphere is uniform when the cavity is concentric with the sphere. However, if the cavity is not concentric, the electric field is not zero despite the absence of enclosed charge within a Gaussian surface. The net electric flux through the Gaussian surface is zero, but this does not imply that the electric field itself is zero; rather, the field varies due to the lack of spherical symmetry. This understanding clarifies the apparent contradiction in the behavior of electric fields in non-uniform configurations.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and flux concepts
  • Knowledge of spherical symmetry in electrostatics
  • Basic principles of electrostatics and charge distribution
NEXT STEPS
  • Study Gauss's Law in detail, focusing on non-uniform charge distributions
  • Explore electric field calculations for non-concentric spherical cavities
  • Learn about the implications of symmetry in electrostatics
  • Investigate the behavior of electric fields between parallel charged planes
USEFUL FOR

Students of physics, particularly those studying electromagnetism, educators explaining electrostatic principles, and anyone interested in advanced concepts of electric fields and charge distributions.

Amith2006
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Homework Statement


This question has already been asked before. The electric field inside a spherical cavity carved out of a larger sphere is uniform which I have derived. What I don't really understand is that if you construct a gaussian surface inside the cavity, it wouldn't enclose any charge. So, there shouldn't any electric field which is contradictory to my previous results. I think I'm missing a subtle point but can't figure out. Thanks in advance.

Homework Equations


The Attempt at a Solution

 
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If the cavity is concentric with the larger sphere, it is uniform - zero.

If the cavity is not concentric, then the thing about the gaussian surface is the fact that you have no enclosed charge means that the NET flux is zero on the surface - not that the flux is zero everywhere. It is not constant over the surface because your problem doesn't have the spherically symmetry necessary.

Here's an intuitive example - two parallel, infinite charged planes. Obviously there's a uniform E-field perpendicular to the planes between them. Construct a gaussian spherical surface between the two planes - no enclosed charge!

That means the net flux through that gaussian sphere is zero - because the flux entering it on one side is the same as the flux exiting it on the other. That does NOT mean the E-field is zero, because again it's not spherically symmetrical so you can't assume the flux is constant over the surface.
 
I get it now. Thanks.
 

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