Electric field inside conductor

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SUMMARY

The electric field inside a spherical conducting shell with inner radius a and outer radius b, containing a centrally-located point charge +Q, is zero for any radius r where a < r < b. This occurs because the induced negative charge on the inner surface and the induced positive charge on the outer surface create an electric field that cancels the outward field from the central charge. The conductor behaves as a limitless source of free charge, ensuring that any net electric field within the conductor is neutralized.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with Gauss's Law
  • Knowledge of conductors and insulators in electrostatics
  • Concept of induced charge distribution in conductors
NEXT STEPS
  • Study Gauss's Law and its applications in electrostatics
  • Learn about electric field lines and their behavior in conductors
  • Explore the concept of induced charges in various geometries
  • Investigate the properties of conductors in electrostatic equilibrium
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Students of physics, particularly those studying electrostatics, educators teaching electric field concepts, and anyone interested in the behavior of electric fields in conductive materials.

bigplanet401
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Homework Statement



A spherical conducting shell of inner radius a and outer radius b contains a centrally-located point charge +Q. Is an electric field present at radii (i) less than a, (ii) between a and b, and (iii) greater than b?

Homework Equations





The Attempt at a Solution



My textbook says the electric field inside a conductor (a<r<b here) is zero, but I can't understand why. In (i), the field is that due to the charge. In (iii), field lines emanate from the surface at right angles (because the induced charge is positive on the outer surface).

In (ii), it seems like the field should be non-zero because of the induced positive charge on the outer surface and the induced negative charge on the inner surface. Wouldn't this create an electric field directed radially inward from r=b to r=a? The textbook says it's zero.

Thanks for your help!
 
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bigplanet401 said:

Homework Statement



A spherical conducting shell of inner radius a and outer radius b contains a centrally-located point charge +Q. Is an electric field present at radii (i) less than a, (ii) between a and b, and (iii) greater than b?

Homework Equations





The Attempt at a Solution



My textbook says the electric field inside a conductor (a<r<b here) is zero, but I can't understand why. In (i), the field is that due to the charge. In (iii), field lines emanate from the surface at right angles (because the induced charge is positive on the outer surface).

In (ii), it seems like the field should be non-zero because of the induced positive charge on the outer surface and the induced negative charge on the inner surface. Wouldn't this create an electric field directed radially inward from r=b to r=a? The textbook says it's zero.

Thanks for your help!

Yes, the induced negative charge on the inner surface and the induced positive charge on the outer surface create a radially inward electric field that is just enough to cancel the radially outward electric field from the central point charge in this region a < r < b.

The point of an ideal conductor is that it can be considered a sort of limitless source of free charge. So, the E-field from the central point charge pushes charges around inside the conductor until they are arranged in such as way as to cancel out the field. If the field were not canceled out, and there were still a NET electric field inside the conductor, then this net electric field would push around even MORE charges until the arrangement was such that the field inside the conductor was zero.
 

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