Electric Field Magnitude at Point P Inside a Charged Sphere

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Homework Help Overview

The discussion revolves around calculating the electric field magnitude at a point inside a uniformly charged insulating solid sphere using Gauss' Law. The problem involves understanding the distribution of charge within the sphere and the application of relevant formulas.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore different formulations of Gauss' Law and question the calculations of enclosed charge. There are attempts to derive the electric field using various approaches, including volume considerations and the relationship between charge and radius.

Discussion Status

Participants are actively engaging with the problem, offering different perspectives on how to approach the calculation. Some have suggested breaking down the problem into logical steps to clarify the relationship between the charge and the electric field. There is no explicit consensus on the correct approach yet.

Contextual Notes

There are indications of confusion regarding the application of Gauss' Law and the calculations of the enclosed charge based on the sphere's geometry. Participants are also considering the implications of the charge distribution within the sphere.

eurekameh
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An insulating solid sphere of radius a = 1.2 m is uniformly charged with charge Q = 4.5 x 10^-6 C. Point P inside the sphere is at a distance r = 0.60 m from the sphere center C. What is the magnitude of the electric field at point P?

So I'm using Gauss' Law:

q,enc = Q[(pi * r^2)/ (pi * a^2)]

int(E dot dA) = q,enc / epsilon,naut
= Q[(pi * r^2)/ (pi * a^2)] / epsilon,naut

E * (pi * r^2) = Q(r^2 / a^2) / epsilon,naut

Thus, E = (Q) / (pi * epsilon,naut * a^2) = 1.12 * 10^5 V/m.

This doesn't seem to be the answer. Anyone know what I did wrong?
 
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Volume varies as the cube of the radius.
 
Now I'm doing E * pi * r^2 = (Qr^3) / (epsilon,naut * a^3), but E is turning out to be 5.62E4 V/m, which is 4 times the correct answer.
 
Rather than trying to do everything at once, why not take logical steps? First, what fraction of the total charge Q is contained in the inner spherical volume of radius r?
 
r^3 / a^3
 
gneill said:
Rather than trying to do everything at once, why not take logical steps? First, what fraction of the total charge Q is contained in the inner spherical volume of radius r?

eurekameh said:
r^3 / a^3

Okay, so given that you know the total charge Q, you now know the fraction of that charge that's within the spherical region with radius r.

Now, given a charge q within that sphere of radius r, what's the resulting electric field at distance r from its center?
 
E = (Qr) / (pi * a^3)
 
Edit:
E = (Qr) / (pi * a^3 * epsilon,naut)
 
Actually, E = kq / r^2 = (kQr) / (a^3) works, but I'm trying to use Gauss' Law.
 
  • #10
eurekameh said:
Actually, E = kq / r^2 = (kQr) / (a^3) works, but I'm trying to use Gauss' Law.

So choose your Gaussian surface and write Gauss' law for for it. You'll find that you need the total charge enclosed by the surface (done above), and the volume of the Gaussian sphere (done above). I suppose it's just a matter of putting the steps in an order that shows the appropriate progression :smile:
 

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