Electric field of a dipole at an offset point

Click For Summary
SUMMARY

The discussion focuses on calculating the electric field of a dipole at specific points along the x-axis and y-axis using Cartesian coordinates. Participants emphasize the importance of correctly applying Coulomb's Law in vector form and analyzing the signs of the components in equations 3 and 5. A key point raised is the handling of the binomial version of the denominator and ensuring accuracy in the signs of the terms, particularly the j-hat components. The conversation highlights the necessity of clear communication and attention to detail in mathematical problem-solving.

PREREQUISITES
  • Coulomb's Law in Cartesian vector form
  • Understanding of electric dipoles
  • Basic knowledge of vector components (i-hat and j-hat)
  • Familiarity with binomial approximation techniques
NEXT STEPS
  • Study the derivation of electric fields from dipoles using Cartesian coordinates
  • Learn about the implications of sign conventions in vector equations
  • Explore the binomial approximation in physics problems
  • Investigate the behavior of electric fields at various distances from dipoles
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism and vector calculus, as well as anyone involved in solving complex electric field problems.

cj
Messages
85
Reaction score
0
Note: Post edited by moderator:

1. Homework Statement

Capture.JPG

Homework Equations


I can't use voltage, nor polar coordinates (got to stick with cartesian).
Cartesian vector form of Coulomb's Law

The Attempt at a Solution



page 1.jpg

page 2.jpg

 
Last edited by a moderator:
Physics news on Phys.org
[ Items related to the initial post's original format removed by moderator ] ...

However, your handwriting and images are fairly clear, and you have taken the trouble to number all of your equations, which helps enormously, so I will answer.

It asks for two specific cases, a point on the x-axis and a point on the y axis. You do not need to work with P in general position.
In your equations (3) and (5), compare the signs on the ##\hat j## terms.
 
Last edited by a moderator:
haruspex said:
It asks for two specific cases, a point on the x-axis and a point on the y axis. You do not need to work with P in general position.
In your equations (3) and (5), compare the signs on the ##\hat j## terms.
Thank you. I appreciate your feedback. It, does, though, not help at all. What I provided is many steps beyond the scope of your suggestion, and focuses on how to handle the binomial version of the denominator, and how to process it. Again, thanks anyway.
 
Last edited by a moderator:
cj said:
It, does, though, not help at all.
Then you have not paid proper attention to my final comment:
haruspex said:
In your equations (3) and (5), compare the signs on the ##\hat j## terms.

[... some text unrelated to the problem at hand deleted by moderator]
 
Last edited by a moderator:
haruspex said:
Then you have not paid proper attention to my final comment:
.
I did; I suspect you didn't read my post in its entirety - or you simply are stumped. I'd follow up with clarifying comments - but there's a ton in my post already.
 
cj said:
I did; I suspect you didn't read my post in its entirety - or you simply are stumped. I'd follow up with clarifying comments - but there's a ton in my post already.
Which post? Your original images or something since? I still don't see anywhere that you admit to having a sign wrong in equation 5.
 
That was a typo: but it's the x-hat term in Eq. 5 (I prematurely assigned a "-" sign to reflect the -x direction of E-; but didn't carry it through).

I disagree; the j-hat terms are indeed correct as written (this has been widely confirmed, and is a moot point).
 
cj said:
I disagree; the j-hat terms are indeed correct as written (this has been widely confirmed, and is a moot point).
Humour me: plug x=0 into equations 3 and 5, and consider y>>a. What do you notice?
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
7
Views
2K
Replies
9
Views
856
Replies
1
Views
2K
Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
14
Views
5K
  • · Replies 18 ·
Replies
18
Views
3K