Electric field of a point of charge

[ibaraku]

Homework Statement

A point charge Q = 16.5uC is at the origin. Find the electric field vector at the point P with coordinates x = 15cm, y = 25cm, z = 0.

Homework Equations

E = kQ/d^2
F = QE

The Attempt at a Solution

Ok, so first to calculate the distance between the origin and point P I used the Pythagorean theorem, which comes out to be 29.15cm, or .2915m

Then I applied the formula above

[(9 x 10^9) (16 x 10^-6)] / [(.15)^2 + (.25)^2] which is equal to --->>> 1694117.647 N/C

so my question is
in order to get the electric field do I just multiply
(1694117.647) (16 x 10^-6) --->>> 27.11

it just doesn't seem right...
thanks

 

[granpa]

why don't you break it down for us and tell us what all these numbers and equations mean.

 

[gendou2]

1694117.647 N/C is the amplitude of the field vector at that point.
The direction of the vector is parallel to the hypotenuse.

 

[ibaraku]

1694117.647 N/C is the amplitude of the field vector at that point.
The direction of the vector is parallel to the hypotenuse.

Ok I see, thanks