Electric Field of Three Point Charges

In summary, for three point charges lying along a circle of radius r at angles of 30°, 150°, and 270°, the resultant electric field at the center of the circle can be expressed as 2k_eq/r^2(sin(30)+1), where the two positive charges contribute a downward electric field and the negative charge also contributes downward.
  • #1
crybllrd
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Homework Statement



Three point charges lie along a circle of radius r at angles of 30°, 150°, and 270° as shown in the figure below. Find a symbolic expression for the resultant electric field at the center of the circle.

23-p-026.gif


Homework Equations



[itex]\vec{E}=\frac{k_{e}q}{r^{2}}[/itex]

The Attempt at a Solution



The two positive charges' horizontal components will cancel out, and their vertical components will combine. This is for the two positive charges:

[itex]=2\frac{k_{e}q}{r^{2}}sin(30)[/itex]

The negative charge is all in the vertical direction.

[itex]=-2\frac{k_{e}q}{r^{2}}[/itex]

I pulled the -2 from -2q out front.

Combining them for the total field:

[itex]=2\frac{k_{e}q}{r^{2}}sin(30)+-2\frac{k_{e}q}{r^{2}}[/itex]

[itex]=2\frac{k_{e}q}{r^{2}}[sin(30)+1][/itex]

How does that look?
 
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  • #2
crybllrd said:
Combining them for the total field:

[itex]=2\frac{k_{e}q}{r^{2}}sin(30)+-2\frac{k_{e}q}{r^{2}}[/itex]

[itex]=2\frac{k_{e}q}{r^{2}}[sin(30)+1)[/itex]

How does that look?

Well, "+-" identical "+" does not look nice :tongue2: Indicate the direction of the contribution of the separate charges to the electric field. So the two positive charges contribute with a downward electric field and that of the negative charge is also downward.

ehild
 
Last edited:

1. What is the formula for calculating the electric field of three point charges?

The formula for calculating the electric field of three point charges is given by E = k * (q1/r1^2 + q2/r2^2 + q3/r3^2), where k is the Coulomb's constant, q1, q2, and q3 are the charges of the three point charges, and r1, r2, and r3 are the distances from the point of interest to each charge.

2. How do the directions of the electric fields from each point charge affect the overall electric field?

The directions of the electric fields from each point charge are vector quantities, meaning they have both magnitude and direction. The overall electric field is determined by the vector sum of the individual electric fields from each point charge. If the electric fields are in the same direction, they will add up, whereas if they are in opposite directions, they will cancel each other out.

3. Can the electric field of three point charges be zero?

Yes, it is possible for the electric field of three point charges to be zero. This occurs when the vector sum of the individual electric fields from each point charge is equal to zero. This can happen when the charges are arranged in a way that the electric fields cancel each other out, or when the distances from the point of interest to each charge are the same.

4. How does the magnitude of the charges affect the strength of the electric field?

The magnitude of the charges directly affects the strength of the electric field. The larger the charges, the stronger the electric field will be. This can be seen in the formula for calculating the electric field, where the charges are in the numerator. A larger charge will result in a larger numerator, leading to a stronger electric field.

5. Can the electric field of three point charges be negative?

Yes, the electric field of three point charges can be negative. This occurs when the vector sum of the individual electric fields from each point charge results in a negative value. This can happen when the charges have opposite signs and are arranged in a way that the electric fields point in opposite directions.

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