Electric field strength and speed

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SUMMARY

The electric field strength within a parallel-plate capacitor is measured at 1.70×104 N/C, with a plate spacing of 1.40 cm. An electron released from rest at the negative plate accelerates towards the positive plate due to the electric field. To calculate the electron's speed upon reaching the positive plate, one must apply Newton's second law (F = ma) and kinematic equations, specifically (vf)2 = (vi)2 + 2ad, where 'a' is the acceleration derived from the electric force. Basic algebra is required to derive the final speed.

PREREQUISITES
  • Understanding of electric field strength and its units (N/C)
  • Familiarity with kinematic equations in physics
  • Knowledge of Newton's second law (F = ma)
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study the relationship between electric fields and forces on charged particles
  • Learn how to derive acceleration from electric field strength
  • Explore advanced kinematic equations for varying conditions
  • Investigate the behavior of electrons in electric fields
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of charged particles in electric fields.

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The electric field strength is 1.70×104 inside a parallel-plate capacitor with a 1.40 spacing. An electron is released from rest at the negative plate.

What is the electron's speed when it reaches the positive plate?
Help please...
 
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You need to combine Forces with Kinematics. We know that F = KE/r and also know that [tex](v_{f})^2 = (v_{i})^2 + 2ad[/tex] and of course, Newton's second law: F = ma. You have everything you need, just use some basic algebra, and that's it.
 

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