Electric Field Strength & Work Calculation: 520V, .8cm

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SUMMARY

The discussion focuses on calculating the electric field strength and work required to move an electron between two plates with a potential difference of 520V and a separation of 0.80cm. The electric field (E) is determined using the formula E = V/d, where V is the potential difference and d is the distance between the plates. The calculated electric field strength is 6500 V/m directed from the positive to the negative plate. Additionally, the work required to move one electron to the negative plate can be calculated using the formula W = qV, where q is the charge of the electron.

PREREQUISITES
  • Understanding of electric field concepts
  • Familiarity with electric potential difference
  • Knowledge of basic physics equations related to electric fields
  • Concept of electron charge (approximately -1.6 x 10-19 C)
NEXT STEPS
  • Learn how to derive electric field strength from potential difference and distance
  • Research the relationship between electric field and work done on charged particles
  • Explore the concept of electric potential energy in electric fields
  • Study the effects of electric fields on charged particles in various configurations
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Students studying physics, particularly those focusing on electromagnetism, as well as educators and anyone interested in understanding electric fields and potential differences.

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Homework Statement


The potential difference between two plates below is 520V. The distance between these two plates is .80cm. (A)What is the strength and direction of the electric field between the two plates? (B) How much work is required to move one more electron to the negative plate?


Homework Equations


NOT SURE IF THESE ARE RELEVANT>
Electric Potential Difference=F/q


The Attempt at a Solution


?
 
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Your equation is not right. That's not E as in electric potential it is E as in electric field. Try looking up potential difference.
 

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