Electric Field Strength & Work Calculation: 520V, .8cm

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KHurst
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Homework Statement


The potential difference between two plates below is 520V. The distance between these two plates is .80cm. (A)What is the strength and direction of the electric field between the two plates? (B) How much work is required to move one more electron to the negative plate?


Homework Equations


NOT SURE IF THESE ARE RELEVANT>
Electric Potential Difference=F/q


The Attempt at a Solution


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Your equation is not right. That's not E as in electric potential it is E as in electric field. Try looking up potential difference.