Electric Field and Conductor Properties

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SUMMARY

The discussion centers on the properties of electric fields and conductors, specifically addressing the net electric flux through a cylindrical insulating material in an external electric field and the behavior of electric fields at the surface of conductors. The consensus is that the net electric flux through the cylinder is zero due to the absence of enclosed charge, as indicated by Gauss' Law. Additionally, the electric field at the surface of a conductor depends on the area, curvature, and total charge, confirming that option e is correct. Understanding these concepts is crucial for solving related physics problems.

PREREQUISITES
  • Understanding of Gauss' Law and its applications
  • Familiarity with electric flux calculations
  • Knowledge of electric field behavior around conductors
  • Basic concepts of charge distribution and surface charge density
NEXT STEPS
  • Study Gauss' Law in detail, focusing on its mathematical formulation and applications
  • Explore electric flux calculations using the formula electric flux = integral[E*dA]
  • Investigate the relationship between electric field intensity and surface curvature
  • Learn about charge distribution effects on electric fields in different geometries
USEFUL FOR

Students of physics, educators teaching electromagnetism, and anyone seeking to deepen their understanding of electric fields and conductor properties.

Soaring Crane
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Homework Statement



A cylindrical piece of insulating material is placed in an external electric field, as shown in the figure. The net electric flux passing through the surface of the cylinder is

a.positive.

b.negative.

c.zero.

Figure : http://i131.photobucket.com/albums/p289/SoaringCrane/Tip23_fig11.gif


Homework Equations



Possibly: electric flux = E*A*cos theta

The Attempt at a Solution



I’m really unsure about this question. Would the net flux be a. positive? The flux on the ends would be 0 because the E and dA vectors are perpendicular to each other while the flux on the wall near the middle will be positive since E and dA are parallel to each other?


Homework Statement



The electric field at the surface of a conductor


a.is parallel to the surface.

b.depends only on the total charge on the conductor.

c.depends only on the area of the conductor.

d.depends only on the curvature of the surface.

e.depends on the area and curvature of the conductor and on its charge.



Homework Equations



This is really a conceptual question. Possibly electric flux = integral[E*dA] = Q_enclosed/epsilon_0

The Attempt at a Solution



Is the correct choice e. depends on the area and curvature of the conductor and on its charge? I know that the electric field intensity increases as the curvature increases. The electric field for an infinitely long sheet is based on the surface charge density, so area and charge (from Gauss’ law) are other factors?

Thanks.
 
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You are trying to work way too hard for the first problem. What IS Gauss' Law?
For the second one, yes it's conceptual. You know it depends on curvature and surface charge density. And you do know a) is false, right? (Why?) So everything is pointing at e) alright.
 
Last edited:
Gauss' law states that the net electric flux for a closed surface is equal to the total electric charge over epsilon_0.
 
Soaring Crane said:
Gauss' law states that the net electric flux for a closed surface is equal to the total electric charge over epsilon_0.

You mean "total charge enclosed in the surface". Right?
 
Last edited:
Yes, Q_enclosed/epsilon_0. What am I doing incorrectly for the first question?
 
You aren't doing anything wrong! But how much charge is enclosed in the cylinder?
 
It does not say how much charge is inside. (Is there even any charge inside??)
 
Exactly! Judging by the phrase "external electric field" and looking at the picture I would say there is no charge inside. Hence?
 
The net electric flux is 0.
 
  • #10
Yes. That would be correct.
 

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