Electric Flux Calculation for Oppositely Charged Circular Plates

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SUMMARY

The discussion focuses on calculating electric flux between two oppositely charged circular plates with a charge of ±1.0 nC, a radius of 5.00 cm, and a separation of 1.00 mm. Electric flux is defined as the product of the electric field and the area through which it passes. The calculation for a circular area of radius 5.00 cm yields a specific value, while the flux for a larger radius of 5.00 meters remains essentially the same due to the uniform electric field between the plates. This phenomenon illustrates the principles of electric field behavior in parallel plate configurations.

PREREQUISITES
  • Understanding of electric flux and its mathematical definition
  • Familiarity with Gauss's Law and its application to closed surfaces
  • Knowledge of electric fields generated by point charges and parallel plates
  • Basic concepts of electrostatics and charge distribution
NEXT STEPS
  • Study the application of Gauss's Law for closed surfaces in electrostatics
  • Learn about electric field calculations for parallel plate capacitors
  • Explore the concept of electric flux in various geometrical configurations
  • Investigate the effects of varying charge distributions on electric fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric flux and its implications in electrostatics.

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Homework Statement


Two circular parallel metal plates are oppositely charged with q = ±1.0 nC. The two plates each have a radius of 5.00 cm and are separated by 1.00 mm. (a) Estimate the electric flux for a circular area of radius 5.00 cm sandwiched between the two plates. (b) Repeat for a circular area of radius 5.00 meters – the result would be essentially the same. Explain why this would be the case.

I don't know how to start. I thought that any charge outside a gauss surface is zero to that surface.
 
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This isn't really a Gauss's Law problem. Gauss's Law deals with flux through closed surfaces. Here, we have an open surface.

HINT: Let's start at the beginning. Can you state the definition of electric flux for me?
 

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