Electric Flux through a Closed Hemisphere Question

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Homework Help Overview

The problem involves calculating the electric flux through a closed hemisphere that is centered at the origin, with an infinite line of charge along the x-axis. The original poster is questioning the correct approach to determining the enclosed charge and the resulting flux.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the enclosed charge using the linear charge density and questions whether the flux should be halved compared to a full sphere. Other participants inquire about the orientation and characteristics of the hemisphere to clarify the application of Gauss's law.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the orientation of the hemisphere and its implications for applying Gauss's law. There is no explicit consensus yet, as questions about the setup remain open.

Contextual Notes

Participants are discussing the implications of the hemisphere being a closed surface and the necessity of understanding its orientation relative to the line of charge.

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Homework Statement


An infinite line of charge is along the entire x-axis has a constant value for λ. A hemisphere is centered at the origin and has a base circle of radius a. What is the electric flux through the hemisphere


Homework Equations



Flux = Q enclosed / ε

The Attempt at a Solution



Q enclosed must be λ* (2a) .. Thus, the answer should be 2λa/ε. Is this right or should we half it.. I mean would this be the same answer if the hemisphere was a full sphere. Thanks for helping!
 
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What's the orientation of the hemisphere? Is it just a hemisphere or is it a closed surface? (Gauss's law requires a closed surface.)
 
It is a closed hemisphere!..
 
ehabmozart said:
It is a closed hemisphere!..
Good. What is its orientation? Is its axis of symmetry parallel to the x-axis?
 

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