An electron is released a short distance above the surface of the Earth. A second electron directly below it exerts an electrostatic force on the first electron just great enough to cancel the gravitational force on it. How far below the first electron is the second? M
F = G(MeMp)/r^2
F = Ke|q1||q2|/r^2
The Attempt at a Solution
I am not sure how to attempt this problem but this is what i thought.
F = (6.67 x 10^-11) (9.11 x 10^-31)(1.67 x 10^-27)/r^2
my problem there is i don't know how to find F to solve for r. its the same way if i use the other formula I still don't know F to solve for r.
I don't understand this at all and what numbers am i suppose to find to do this.