A proton is initially at rest (in a vacuum) in a uniform electric field of magnitude 1.30 10^3 N/C. (a) Calculate the force applied to the proton by the field. ANSWER: 2.08E-16 N (b) Apply Newton's second law to calculate the acceleration of the proton. (Don't be surprised if the acceleration is large. It isn't applied for a very long time.) ANSWER: 1.24E11 m/s^2 (c) Calculate the time it takes for the proton to move 1 cm in this field, starting from rest. (Hint: The acceleration is uniform.) in part c i cannot figure out how to find the uniform acceleration. the equation given to find the time it takes for the proton to move 1cm in this field is x = 1/2at^2 and i'm solving for t. 0.01 m = 1/2 (Vf - Vi) t^2 0.01 m = 1/2 (1.30x10^3 - 0) t^2 but the answer i got was wrong. what am i doing wrong to find the time it takes for the proton to move 1 cm?