Electric Potential in an Insulating Sphere

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SUMMARY

The discussion focuses on calculating the electric potential at the inner surface of a conducting shell surrounding a uniformly charged insulating sphere. The insulating sphere has a radius of 4.3 cm and a charge density of -421 μC/m³, resulting in an electric field of -13130.92 N/C at a distance of 31 cm from the origin. The user struggles with determining the electric potential at the inner surface of the conducting shell, which is incorrectly calculated by assuming the potential at the inner radius is equal to that at the outer radius. The correct approach involves integrating the electric field considering the influence of the conducting shell.

PREREQUISITES
  • Understanding of electric fields and potentials in electrostatics
  • Familiarity with Gauss's Law and its application to spherical symmetry
  • Knowledge of integration techniques for calculating electric potential
  • Proficiency in using Coulomb's constant (k) and charge density calculations
NEXT STEPS
  • Study the application of Gauss's Law for electric fields in spherical coordinates
  • Learn about the relationship between electric field and electric potential
  • Explore the concept of electric potential in conductors and the role of induced charges
  • Review integration techniques for calculating electric potential from electric fields
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding electric fields and potentials in conductive and insulating materials.

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Homework Statement


A solid insulating sphere of radius a = 4.3 cm is fixed at the origin of a co-ordinate system as shown. The sphere is uniformly charged with a charge density ρ = -421 μC/m3. Concentric with the sphere is an uncharged spherical conducting shell of inner radius b = 14.6 cm, and outer radius c = 16.6 cm.
h6_sphere1.png


1) What is Ex(P), the x-component of the electric field at point P, located a distance d = 31 cm from the origin along the x-axis as shown? I got the answer correct: -13130.92 N/C

2) What is V(b), the electric potential at the inner surface of the conducting shell? Define the potential to be zero at infinity.

I am having trouble with number 2. I only have one more chance to submit an answer for number 2 so I can really use some help.

Homework Equations


ΔV=-∫E*dr
E = kQ/r

The Attempt at a Solution


For number 2 I took the integral infinity to c ∫E*dr and from c to b (which I assumed to be 0 since it is the shell) and then to calculate the integral I got (k(Q(calculated in q1)+q(of inner sphere determined by density)/c). I got -7.119E14. What did I do wrong?
For my first try I did (kq(innersphere))/b and got the message " It looks like you have calculated the potential at the inner radius of the shell to be equal to the potential at r = c produced by the insulating sphere by itself. The conducting shell plays a role here. Go back to the definition of the potential to determine the answer." But I'm not quite sure what that means.
I have also just considered that it might be the answer to number 1 (if that would be the E for the region) divided by c. Does that make sense? I'm kinda confused and afraid to guess.[/B]
 
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