Electric Potential of a Spherical Shell of Charge

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SUMMARY

The electric potential of a spherical shell of charge can be analyzed based on its thickness and charge distribution. For a spherical shell with inner radius 'a' and outer radius 'b', the electric potential behaves differently depending on the distance 'r' from the center. When 'r > b', the shell can be treated as a point charge. When 'r < a', the potential remains constant. For the range 'a < r < b', both the electric field and potential vary, requiring integration to determine the values based on the charge within that radius.

PREREQUISITES
  • Understanding of electric potential and electric fields
  • Familiarity with spherical coordinates in physics
  • Knowledge of charge density and its implications
  • Ability to perform integration in the context of physics
NEXT STEPS
  • Study the concept of electric potential for non-conducting spherical shells
  • Learn how to calculate electric fields using Gauss's Law
  • Explore charge density calculations for various geometries
  • Practice integration techniques for electric field and potential calculations
USEFUL FOR

Students preparing for physics exams, particularly those focusing on electromagnetism, as well as educators teaching concepts related to electric fields and potentials in spherical geometries.

Polarbear
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Ok if you have a spherical shell of radius R with an even distribution of charge then outside the shell at a distance r where r>R I get that the shell can be treated as a point charge and inside the sphere (r<R) the electric potential will be constant.
All my notes cover when the shell has no thickness and I was thinking what happen if the spherical shell did have thickness (say inner radius a and outer radius b)? When r is greater then b can the shell still be treated as a point charge? How about when a<r<b?
 
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If the charge is uniformly distributed throughout the (nonconducting) shell:

(r > b) Treat as a point charge

(r < a) potential will be constant

(a < r < b) the field (and potential) will vary throughout this range; you'll need to integrate. (The field at a radius r depends only on the charge within that radius; the field is that of a point charge, but only the charge within r contributes to the field.)
 
Thanks for just clearing that up for me. I've managed to find a question on this (I'm getting practise in before mid-year exams) however it deals in terms of charge density. Is it just as simple as finding Q in terms of the sphere (volume of shell at such and such density).
 
Right. You should be able to work with either total charge Q or with the charge density. As an exercise, you might want to find the field as a function of radius for a uniform ball of charge density \rho.
 

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