Electric Potential Problem - Fixed Template

AI Thread Summary
The discussion revolves around calculating the distance "x" from an electric charge q1 where the net electric potential is zero, given another charge q2 at distance "d." The user attempts to solve the problem using the equation for electric potential, setting the total potential to zero. They derive the equation 3d = 4x, leading to the solution x = 3d/4. Feedback indicates that while the approach is mostly correct, there are minor errors in notation and parentheses that need addressing. Overall, the solution is affirmed as correct with some clarification needed for precision.
Zackkkkkk
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Homework Statement


An electric charge q1 (-6e) is located at the origin. A second electric charge q2 (+2e) is located a distance "d" from the origin. In terms of "d", what is the distance "x" from q1 where the net electric potential is zero? Assume for this problem that x<d.2.Relevant equations
I need a solid explanation on how to do this problem properly. I have a strong feeling that this can't be right (my attempt). I need to be able to understand and work problems like this for my upcoming exam. Any help would be appreciated.

The Attempt at a Solution


Vtotal = V1 + V2.
If Vtotal = 0 then V1+V2=0.
V1-V2
kq1/x = - kq2/d-x
q1/x = - q2/d-x
(q1(d-x))/(-q2) = x
3(d-x) = x
3d = 4x
(3d/4) = x[/B]
 
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Zackkkkkk said:

Homework Statement


An electric charge q1 (-6e) is located at the origin. A second electric charge q2 (+2e) is located a distance "d" from the origin. In terms of "d", what is the distance "x" from q1 where the net electric potential is zero? Assume for this problem that x<d.2.Relevant equations
I need a solid explanation on how to do this problem properly. I have a strong feeling that this can't be right (my attempt). I need to be able to understand and work problems like this for my upcoming exam. Any help would be appreciated.

The Attempt at a Solution


Vtotal = V1 + V2.
If Vtotal = 0 then V1+V2=0.
V1-V2 [/B]##\quad \quad ## Looks like a missing "=" sign, V1 = -V2
kq1/x = - kq2/(d-x)
q1/x = - q2/(d-x)
(q1(d-x))/(-q2) = x
3(d-x) = x
3d = 4x
(3d/4) = x
Other than what appears to be a typo above, and the lack of some needed sets of parentheses, that looks good.

I'm pretty sure that the final answer is correct.
 
SammyS said:
Other than what appears to be a typo above, and the lack of some needed sets of parentheses, that looks good.

I'm pretty sure that the final answer is correct.
Thank you for your input, friend.
 
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