Electric potential related to electric field question

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SUMMARY

The discussion focuses on calculating the electric field and electric potential for a non-conducting sphere with a non-homogeneous charge density defined as ρ(r) = r. The electric field inside the sphere is determined to be E = r² / 4ε₀, while outside it is E = R⁴ / 4ε₀r². For the electric potential, the inside potential is V = -r³ / 12ε₀, and the outside potential is V = R⁴ / 4ε₀r. The inconsistency between the two potential equations at the boundary suggests a misunderstanding of the integration process and the importance of the constant of integration in determining absolute potential.

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David0709
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Homework Statement


(i) Consider a non-conducting sphere of radius R with non-homogeneous charge density ρ = ρ(r) = r, where r is the radial co-ordinate.

  1. (a) Find the electric field inside and outside of the sphere
  2. (b) Find and plot the electric potential inside and outside of the sphere

Homework Equations


[/B]
E=−∇V
E = KQ1Q2/r^2
V = KQ1Q2/R

The Attempt at a Solution

For part a) Field inside the sphere = r^2 / 4ε0
Outside the sphere R^4 / 4ε0r^2

With regards to part b)
I am aware that E=−∇V

So applying this formula we have:
Outside sphere:
R^4 /4ε0 r
Inside sphere potential
-r^3 /12ε0

However when we let R = r we see these two equations for potential do not agree suggesting something (am not sure what ) is wrong.

Any help would be appreciated
 
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David0709 said:
these two equations for potential do not agree
Potential is always relative to some arbitrary zero, often taken as the potential at infinity.
To put it another way, going from field to potential is an integration, and an integral has a constant of integration, resolved by the bounds. The result of that is just the difference in potential between the endpoints, not an absolute potential.
 
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