Electrical analog and impedance

[Shackleford]

Let me redraw the circuit in the standard way. See the picture attached.
Now can you calculate the impedance from the circuit?

The answer the back of the book has is very long and nasty. I don't know how to get their answer.

 

[hikaru1221]

Well if you don't remember how to calculate impedance, you'd better review your knowledge Hint: Use the complex forms of impedance:
$$Z_R = R$$
$$Z_L = jL\omega$$
$$Z_C = -\frac{j}{C\omega}$$

 

[Shackleford]

Well if you don't remember how to calculate impedance, you'd better review your knowledge Hint: Use the complex forms of impedance:
$$Z_R = R$$
$$Z_L = jL\omega$$
$$Z_C = -\frac{j}{C\omega}$$

Well, I put an equation for impedance in a previous post. The only difference is it's not in complex form. Why does it have to be in complex form?

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-25233241.jpg?t=1285475708

 

[hikaru1221]

That's not the right one. That formula is only true for the case that there are only 3 elements R, L, C in series with the source (RLC circuit). It doesn't apply to this case where the circuit is much more complicated.

 

[Shackleford]

That's not the right one. That formula is only true for the case that there are only 3 elements R, L, C in series with the source (RLC circuit). It doesn't apply to this case where the circuit is much more complicated.

Okay. Let me see what I can dig up in my Physics II book.

 

[Shackleford]

Nope. The Physics II book only covers Series LRC circuit. This of course is a combination series and parallel LRC circuit.