Kepler's Third Law and centripetal acceleration

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SUMMARY

The discussion centers on the application of Kepler's Third Law in the context of centripetal acceleration for two stars in a circular orbit. The user attempts to derive the orbital velocity (v) in terms of distance (d) and the orbital period (τ), using the relationship v = (π*d)/τ. The user expresses difficulty in progressing with the problem, indicating a need for clearer understanding of the gravitational forces at play and their relation to centripetal acceleration.

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Shackleford
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I'm not getting very far with these problems. Don't know what my problem is.

Given a circular orbit, the centripetal acceleration is given by the gravitational force between the two stars. I chose the center to be halfway between the stars d/2.

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-13225621.jpg?t=1284437088

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-13225642.jpg?t=1284437089
 
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Try writing v in terms of d and τ.
 
vela said:
Try writing v in terms of d and τ.

pi*d = vt

(1/t)*pi*d = v

v = pi*d*τ

That doesn't get me anywhere.
 
Last edited:

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