What is the value of N when evaluating the integral for thermal photons?

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SUMMARY

The integral for thermal photons evaluates to a polylogarithm, specifically \text{Li}_3(1), which is equivalent to the Riemann zeta function value \zeta(3). The integral simplifies to 2.404, which directly determines the value of N in this context. Key resources include the Wikipedia pages on polylogarithms and the Riemann zeta function for further understanding. This discussion clarifies the relationship between these mathematical concepts and their applications in evaluating integrals.

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Shackleford
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I'm not sure how to evaluate this integral.

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110317_145314.jpg?t=1300391815

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110317_145259.jpg?t=1300391802
 
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Thanks. I had to rearrange and solve for just the integral, which is 2.404, and use that to show what N equals.
 

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