Electrical, Circuits, Ohmslaw etc help

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Homework Help Overview

The discussion revolves around calculating the resistance of a copper conductor with a specified length and cross-sectional area, using the resistivity of copper. Participants are seeking clarification on the relevant formulas and concepts involved in the calculation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to apply the resistivity formula but expresses confusion about the calculations and the meaning of the terms involved. Some participants suggest looking up the resistivity formula and emphasize the importance of using correct units for the cross-sectional area.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on the resistivity formula and the need to convert units. There is a recognition of the need for further clarification, as multiple interpretations of the problem are being explored.

Contextual Notes

There are indications that the original poster may not have received adequate instruction on the topic, leading to uncertainty about the application of the formula and the necessary unit conversions.

whybeahero
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Electrical, Circuits, Ohmslaw etc help please

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8m.


Homework Equations


This is all the information I have gotten from my teacher and i was wondering if anybody here can show me the formula and the answers to the questions.


The Attempt at a Solution


I would probably do something like 1.72 x 10^-8 X 200 or something i got no clue even for the other questions.
 

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You need to use the resistivity formula, should easily be able to look it up.

Make sure you use the units of the CSA correctly.
 
Last edited:


Ye the thing is I have no clue on how to work that out, or what that means lol the teacher didn't explain it on how to calculate it or anything, so can you show me how to work it out please.
 


whybeahero said:

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8m.

Homework Equations


This is all the information I have gotten from my teacher and i was wondering if anybody here can show me the formula and the answers to the questions.

The Attempt at a Solution


I would probably do something like 1.72 x 10^-8 X 200 or something i got no clue even for the other questions.

attachment.php?attachmentid=33099&d=1300180938.png


attachment.php?attachmentid=33100&d=1300180938.png

In the future, please post separate questions as separate threads.

For question #1: there is a formula for combining multiple resistors in series, to get the total resistance RT. Check your textbook or class lecture notes, it is a standard formula that any introductory physics textbook will have.
 


whybeahero said:

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8m.
...
Has your teacher every written something like the following? Maybe it's in your textbook.

[tex]R=\frac{\,\rho\,\ell}{A}\ ,[/tex] where ρ is the resistivity and A is the cross-sectional area ?


.
 


whybeahero said:

Homework Statement


Find the resistance of a copper conductor 300m in length if it has a CSA of 4mm2. The resistivity of copper is 1.72 x 10^-8 Ωm.

Ohm (Ω) is the unit of resistance (R). Resistivity (ρ) is the resistance of a rod of 1 m length and 1 m2 cross section. The resistance is directly proportional to the length and inversely proportional to the cross sectional area (A).

R=ρl/A.

Calculate the resistance of that cooper wire. ρ=1.72 x 10^-8 Ωm. You have to plug in the given data, but first transform the area from mm2 to m2. Go ahead.

ehild
 

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