- #1
Noelani2306
- 4
- 0
Hello everyone,
There is an electrical field inside and outside (at the same time) the spherical hollow conductor when we place positive or negative charge inside, isn't it?
I know this is because of the induced charges on the inner and outer surfaces of the conductor. There is no field inside the conductor itself, but there are field lines "exiting" the positive part on the outer surface of the conductor which, consequently, makes the field exist outside of it.
But why does not this work in the reverse way?
Let me say this: when we place a charge (positive or negative) outside of the spherical conductor, or otherwise, when we place this conductor inside the field lines (External Field lines, i.e two parallel opposite charged plates, as an example), electirc field is not present inside the conductor itself again as in the previous case, but now, they do not enter the empty space inside...?
they skip the conductor again but not pass the conductor and present inside the shell? Why?
There is an electrical field inside and outside (at the same time) the spherical hollow conductor when we place positive or negative charge inside, isn't it?
I know this is because of the induced charges on the inner and outer surfaces of the conductor. There is no field inside the conductor itself, but there are field lines "exiting" the positive part on the outer surface of the conductor which, consequently, makes the field exist outside of it.
But why does not this work in the reverse way?
Let me say this: when we place a charge (positive or negative) outside of the spherical conductor, or otherwise, when we place this conductor inside the field lines (External Field lines, i.e two parallel opposite charged plates, as an example), electirc field is not present inside the conductor itself again as in the previous case, but now, they do not enter the empty space inside...?
they skip the conductor again but not pass the conductor and present inside the shell? Why?