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Electrical Potential of a uniformly charged spherical shell
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[QUOTE="Gene Naden, post: 6016836, member: 640664"] OK, there are not other charges nearby. Still you have the charge on the surface, creating a potential. Your integral ##\int \vec{E} \cdot dl## only gives the difference between the potential at the two endpoints of the integration. What this shows is that the potential is the same at the center as it is at the surface; it doesn't show that it is zero. You could integrate from infinity (where the potential is assumed to be zero) up to the surface. [/QUOTE]
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Electrical Potential of a uniformly charged spherical shell
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