A 1.0 E -6 F capacitor with a charge of 10.0 micro C is connected to a 1.0 H inductor at t = 0. The discussion focuses on comparing the potential energy of the capacitor and the inductor at t = 10 seconds. The potential energy of the capacitor is calculated using the formula V = Q / C, where V is voltage, Q is charge, and C is capacitance. The participants suggest that the configuration of the circuit (series or parallel) significantly impacts the energy comparison, emphasizing the need for clarity on the circuit's arrangement.
PREREQUISITESStudents and professionals in electrical engineering, physics enthusiasts, and anyone studying circuit theory and energy dynamics in capacitive and inductive systems.
Partap03 said:A 1.0 E -6 F capacitor has a charge of 10.0 micro C. It is connected to a 1.0 H inductor at t = 0. Compare the potential energy of the capacitor to the potential energy of the inductor at t = 10s. Which energy is greater?
Partap03 said:First of all thanks.
My thoughts
I know that potential energy is basically voltage across each component.
Also, C = Q / (change in V) ; C is the capacitance, Q is the charge, and V is volts.
solving for change in V and we get
V = Q / C
Am I going in the right direction?
LowlyPion said:First of all I don't know how it's connected. Is the inductor in || to the capacitor? What is the circuit?
Partap03 said:That's all the problem says. Let's assume that it is in series then how would I approach the problem?