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Reduction half reaction : Cu2++2e- -> Cu(s)
I have a doubt in using the reference electrode.
For example if I have the calomel electrode (ESCE=0.24V) how do I use it with the copper half cell? Are these reactions correct?
Cu2++2e- -> Cu(s)
2Hg+2Cl -> Hg2Cl2+2e-
To get Ecell=0.24+ECu|Cu2+
I have a doubt in using the reference electrode.
For example if I have the calomel electrode (ESCE=0.24V) how do I use it with the copper half cell? Are these reactions correct?
Cu2++2e- -> Cu(s)
2Hg+2Cl -> Hg2Cl2+2e-
To get Ecell=0.24+ECu|Cu2+
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