Electrochemistry: reference electrode

In summary, the reduction half reaction is Cu2++2e- -> Cu(s). The conversation discusses using a reference electrode, specifically the calomel electrode, in conjunction with the copper half cell. The correct reactions for the calomel electrode and copper half cell are Cu2++2e- -> Cu(s) and 2Hg+2Cl -> Hg2Cl2+2e-. The cell potential is determined by drawing a potential line and marking the potentials of both half cells, with the cell potential being the distance between them. The question posed is about the correctness of these reactions, with a correction for a typo in the second reaction.
  • #1
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Reduction half reaction : Cu2++2e- -> Cu(s)
I have a doubt in using the reference electrode.
For example if I have the calomel electrode (ESCE=0.24V) how do I use it with the copper half cell? Are these reactions correct?
Cu2++2e- -> Cu(s)
2Hg+2Cl -> Hg2Cl2+2e-
To get Ecell=0.24+ECu|Cu2+
 
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  • #2
Draw a potential line - just like a horizontal axis of the plot.

Mark potentials of both half cells.

Cell potential is the distance between them.
 
  • #3
Borek said:
Draw a potential line - just like a horizontal axis of the plot.

Mark potentials of both half cells.

Cell potential is the distance between them.
My question is different. It's about the cell reaction. Not finding the potential from graph.
 
  • #4
You have already listed both half cell reactions. If you need a full one, just combine them.
 
  • #5
Borek said:
You have already listed both half cell reactions. If you need a full one, just combine them.
My question : Are those reactions correct?
I'll edit the post.
 
  • #6
No such thing as Cl in the second reaction, but I guess it is just a typo.
 
  • #7
Borek said:
No such thing as Cl in the second reaction, but I guess it is just a typo.
Sorry its cl-
 

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