Electromagnetic force and some trig

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SUMMARY

The discussion focuses on calculating the charge of two equally charged pith balls, each with a mass of 1.5 g, in equilibrium at a distance of 2.6 cm apart, with the suspended ball making a 20-degree angle with the vertical. The relevant equation used is Coulomb's law, represented as N = (k(C1C2)/r²), where k is 9 x 10⁹ N m²/C². The participant identifies the need to resolve forces into horizontal and vertical components to solve for the unknowns, specifically the electrostatic force (N) and the charge (x).

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  • Basic trigonometry for resolving forces into components
  • Understanding of equilibrium conditions in physics
  • Knowledge of vector quantities and their properties
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Homework Statement



The diagram below shows two pith balls, equally charged and each with a mass of 1.5 g. While one ball is suspended by a thread, the other is brought close to it and a state of equi- librium is reached. In that situation, the two balls are separated by 2.6 cm and the thread attached to the suspended ball makes an angle of 20 ̊ with the vertical. Calculate the charge on each of the pith balls.

Homework Equations



N = (k(C1C2)/r2

where k = 9 * 109

The Attempt at a Solution



My problem here is that I'm dealing with unknowns on both sides of the equation. I have to find out N and x.

N = (9*10^9(x^2))/1.3^2

I don't know why they give us the information that the angle is 20 degrees. In any case I figured out the dimensions of the triangle which are

7.2, 2.6, 7.65

but I can't figure out how that helps me.
 
Physics news on Phys.org
Force is a vector quantity.

There are three forces involved.

Break the forces down into horizontal and vertical components. (That's why you need to know the angle.)
 

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