Physics - Determine Pith Ball Charges

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SUMMARY

The discussion focuses on calculating the charge on two equally charged pith balls, each with a mass of 1.5g, in a state of equilibrium. The balls are separated by a distance of 2.6cm, with the suspended ball making an angle of 20 degrees with the vertical. The relevant equation used is Coulomb's Law, expressed as F = (kQ1Q2)/(r^2), where k is Coulomb's constant. To solve the problem, one must analyze the forces acting on the suspended ball and apply the conditions for equilibrium.

PREREQUISITES
  • Understanding of Coulomb's Law and electrostatic forces
  • Basic knowledge of equilibrium conditions in physics
  • Ability to analyze forces using free-body diagrams
  • Familiarity with trigonometric functions to resolve forces at angles
NEXT STEPS
  • Study the derivation and application of Coulomb's Law in electrostatics
  • Learn how to construct and interpret free-body diagrams for equilibrium problems
  • Explore the concept of tension in strings and its role in equilibrium scenarios
  • Investigate the relationship between charge, force, and distance in electrostatic interactions
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding electrostatic forces and equilibrium analysis in mechanics.

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Homework Statement


Two pith balls equally charged and each with mass of 1.5g. While one ball is suspended by a thread, the other is brought close to it and a state of equilibrium is reached. In that situation, the two balls are separated by 2.6cm and the thread is attached to the suspended ball makes an angle of 20deg with the vertical. Calculate the charge on each of the pith balls.

m = 1.5*10^-3kg
d = 0.026m


Homework Equations


F = (kQ1Q2)/(r2)


The Attempt at a Solution


I tried finding the force by the work done formula since we have an angle we could include, but i do not get any further than that.
 
Last edited:
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I don't think you can get it that way because you have no means of calculating the work done by the hand pushing the stationary ball.
Use forces. Begin with a diagram of the three forces on the suspended ball when equilibrium is reached. Then write that the sum of the vertical forces is zero and the sum of the horizontal forces is zero (because F=ma and there is no acceleration).
 

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