Electromagnetic forces, finding alpha.

Click For Summary
SUMMARY

The discussion focuses on determining the value of alpha when a third charge is placed at the origin, resulting in zero net force. The problem involves two charges, Q and 5Q, and utilizes Coulomb's Law, expressed as F = k Qa Qb / d^2, to analyze the forces acting on the charge at the origin. Participants seek clarification on the calculations and the application of the law to find the conditions under which the net force is zero.

PREREQUISITES
  • Coulomb's Law for electrostatic forces
  • Understanding of charge interactions
  • Basic algebra for solving equations
  • Concept of net force in electrostatics
NEXT STEPS
  • Study the application of Coulomb's Law in various charge configurations
  • Learn how to calculate net forces in electrostatic systems
  • Explore the concept of equilibrium in electrostatic forces
  • Investigate graphical methods for visualizing charge interactions
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and tutors looking to enhance their understanding of electrostatic forces and charge interactions.

sphys4
Messages
21
Reaction score
0

Homework Statement



When a third charge is placed at the origin, it is found that the force on it is zero. Find alpha?

Two charges Q and 5Q are located as shown in the figure below.
https://chip.physics.purdue.edu/protected/GiordanoEMimg/chapter17/17prob16.jpg



If possible, please show work so i can learn how to do it. Thanks!


Homework Equations





The Attempt at a Solution


I know that force varies as a function of charge and inversely proportional to square of distance.
So i need to use this equation somehow:
F = k Qa Qb / d^2

 
Physics news on Phys.org
That link can only be accessed by Purdue University students. Can you attach the image instead?
 
28ugzsj.jpg
 
So suppose that some charge, q, was placed at the origin. What would be the formula for the force on it due to the charge Q? (And for the sake of argument, suppose for now that all the charges, q, Q, and 5Q are positive).
 

Similar threads

Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
16K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
8
Views
1K
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K