Electromagnetic Induction in AC circuits

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Homework Help Overview

The discussion revolves around electromagnetic induction in AC circuits, specifically focusing on a series circuit containing a resistor, capacitor, and inductor connected to a variable frequency AC source. Participants are exploring the conditions for maximum current and the effects of changing capacitance on current values.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the frequency for maximum current and the corresponding rms current values, but expresses difficulty in obtaining the correct frequency. Other participants inquire about the calculated frequency and the rationale behind dividing by the capacitive reactance (XC) to find the current.

Discussion Status

Participants are actively engaging with the problem, asking clarifying questions about the calculations and the underlying principles. There is no explicit consensus reached, but the discussion is generating insights into the relationships between frequency, reactance, and current in AC circuits.

Contextual Notes

There is a mention of the original post being dated back to 1 April 2010, which some participants note as a potential factor in the discussion's relevance.

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A 9.7 Ω resistor, a 10.8 µF capacitor, and a 27.9 mH inductor are connected in series with a 120 V (rms) source with variable frequency.
(a) At what frequency will the current be maximum?

Hz



(b) Find the maximum rms current.

A



(c) Suppose you now replace the 10.8 µF capacitor by a 22.0 µF capacitor. What is the new value of the rms current?

A





a ) frequency f = 1 / 2π √ L C
= 1/ 2π √27.9 mH * 10.8μF
= _____ Hz cannot get right frequency
b ) Maximum rms current Irms = Vrms / XC
XC = 1/ 2π f C
= 1/ 2π * f Hz * 10.8μF
= _____ Ω
Irms = 120 V / XC Ω
= ____
c ) Maximum rms current Irms = Vrms / XC
XC = 1/ 2π f C
= 1/ 2π * f Hz * 22.0μF
= ___ Ω
Irms = 120 V / XC Ω
 
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What value frequency did you calculate? What did they provide as the correct answer?

Why do you divide by Xc to get the current?
 
scottdave said:
What value frequency did you calculate? What did they provide as the correct answer?

Why do you divide by Xc to get the current?
Note that Post #1 is dated 1 April 2010!
 
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Steve4Physics said:
Note that Post #1 is dated 1 April 2010!
Ha! :woot: These Unanswered Questions just show up... and I'm so into trying to help - I forget to look at the date.
 
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