Electromagnetic Waves in Spherical Coordinates

Click For Summary
The discussion revolves around finding the magnetic field associated with a time-dependent electric field using Faraday's law. The user is confused about the instruction to "set to zero" a time-dependent component of the magnetic field that is not determined by Faraday's law. The electric field given is periodic, and the user successfully calculates the curl of the electric field to derive the magnetic field. However, they are uncertain about the implications of disregarding certain components of the magnetic field. Clarification is sought on whether the instruction might instead refer to ignoring a time-independent part of the magnetic field.
BOAS
Messages
546
Reaction score
19
Hello,

I am trying to find the magnetic field that accompanies a time dependent periodic electric field from Faraday's law. The question states that we should 'set to zero' a time dependent component of the magnetic field which is not determined by Faraday's law. I don't understand what is meant by this.

1. Homework Statement

Consider the following periodically time-dependent electric field in free space, which describes a certain kind of wave.

##\vec E (r, \theta, \phi, t) = A \frac{\sin \theta}{r} \cos(kr - \omega t) \hat \phi##, where ##\omega = ck##

(a) Show that, for r > 0, E~ satisfies Gauss’s law with no charge density.
From Faraday’s law, find the magnetic field. Ignore (set to zero) a time dependent part of the B~ -field not determined by Faraday’s law.
(b) Compute the Poynting vector ##\vec S##.
(c) Calculate ##\bar S##, the average of ##\vec S## over a period ##T = 2π/ω ##.
(d) Find the flux of ##S##through a spherical surface of radius ##r## to determine the total power radiated.

Homework Equations

The Attempt at a Solution


[/B]
Part (a) is obvious because the ##\hat \phi## component has no dependence on ##\phi##

part(b)

Given ##\vec E (r, \theta, \phi, t) = A \frac{\sin \theta}{r} \cos(kr - \omega t) \hat \phi##.

I use Faraday's law ##\vec \nabla \times \vec E = - \frac{\partial \vec B}{\partial t}## and the expression of the curl in spherical polar coordinates to find that;

##\vec \nabla \times \vec E = \frac{2A \cos \theta}{r^2} \cos(kr - \omega t) \hat r + kA \sin \theta \sin(kr - \omega t) \hat \theta##.

Integrating with respect to time to find ##\vec B## yields;

##\vec B = - [\frac{2A \cos \theta}{r^2} \hat r \int \cos(kr - \omega t)dt + kA \sin \theta \hat \theta \int \sin(kr - \omega t)dt]##

##\vec B = \frac{2A \cos \theta}{r^2 \omega} \sin(kr - \omega t) \hat r - \frac{kA \sin \theta}{\omega} \cos(kr - \omega t) \hat \theta + C##

I think that this is the magnetic field, but I haven't used the piece of information given in the question about 'setting the time dependent component to zero'.

What does that piece of information mean here?

Thank you.
 
BOAS said:
Hello,

I am trying to find the magnetic field that accompanies a time dependent periodic electric field from Faraday's law. The question states that we should 'set to zero' a time dependent component of the magnetic field which is not determined by Faraday's law. I don't understand what is meant by this.

1. Homework Statement

Consider the following periodically time-dependent electric field in free space, which describes a certain kind of wave.

##\vec E (r, \theta, \phi, t) = A \frac{\sin \theta}{r} \cos(kr - \omega t) \hat \phi##, where ##\omega = ck##

(a) Show that, for r > 0, E~ satisfies Gauss’s law with no charge density.
From Faraday’s law, find the magnetic field. Ignore (set to zero) a time dependent part of the B~ -field not determined by Faraday’s law.
(b) Compute the Poynting vector ##\vec S##.
(c) Calculate ##\bar S##, the average of ##\vec S## over a period ##T = 2π/ω ##.
(d) Find the flux of ##S##through a spherical surface of radius ##r## to determine the total power radiated.

Homework Equations

The Attempt at a Solution


[/B]
Part (a) is obvious because the ##\hat \phi## component has no dependence on ##\phi##

part(b)

Given ##\vec E (r, \theta, \phi, t) = A \frac{\sin \theta}{r} \cos(kr - \omega t) \hat \phi##.

I use Faraday's law ##\vec \nabla \times \vec E = - \frac{\partial \vec B}{\partial t}## and the expression of the curl in spherical polar coordinates to find that;

##\vec \nabla \times \vec E = \frac{2A \cos \theta}{r^2} \cos(kr - \omega t) \hat r + kA \sin \theta \sin(kr - \omega t) \hat \theta##.

Integrating with respect to time to find ##\vec B## yields;

##\vec B = - [\frac{2A \cos \theta}{r^2} \hat r \int \cos(kr - \omega t)dt + kA \sin \theta \hat \theta \int \sin(kr - \omega t)dt]##

##\vec B = \frac{2A \cos \theta}{r^2 \omega} \sin(kr - \omega t) \hat r - \frac{kA \sin \theta}{\omega} \cos(kr - \omega t) \hat \theta + C##

I think that this is the magnetic field, but I haven't used the piece of information given in the question about 'setting the time dependent component to zero'.

What does that piece of information mean here?

Thank you.
Are you sure they did not mean to say "set to zero a time INdependent part of B?? That would make more sense (note that you did that by not including a constant of integration)
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 11 ·
Replies
11
Views
1K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
3
Views
1K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
927
  • · Replies 21 ·
Replies
21
Views
2K
Replies
1
Views
2K