1. A 0.034 kg copper rod is hung by two wires and placed in a constant magnetic field. A current of 14 A runs through the 0.050 m long copper rod, making it hang at an angle of 34° from the vertical as attached in the diagram. What is the magnetic field strength holding the copper rod in this position? A. 27×10-1 T B. 32×10-1 T C. 39×10-1 T D. 48×10-1 T 2. Relevant equations [itex]\phi[/itex]=B×Acosa F=IlB 3. The attempt at a solution The thing is, I don't really know where to start. I know that the rod is at 34° (not perpendicular), so I know the formula [itex]\phi[/itex]=B×Acosa has to be involved somehow. However, I'd only be solving for [itex]\phi[/itex] and I don't know the area so that really isn't very helpful. I'm also given I and l to find B, and the only equation that looks has these variables is F=IlB. But that would me I need to find force and the other equation is F=QvB and we don't have many variables in that one.