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**Electron and matter waves: WE NEED HELP!!!**

## Homework Statement

Calculate the de Broglie wavelength of (a) a 1.00Kev electron, (b) a 1.00Kev photon, and (c) a 1.00KeV neutron

## Homework Equations

K = mv^2 / 2

p = mv

p = sqrt 2KM

m of electron is 9.11 * 10^-31 kg

1 ev = 1.6 * 10^-19 Joules

change in Lamda = h / p

h = 6.63 *^-34

## The Attempt at a Solution

Is this correct. Here's what we tried.

)

change in lamda = 6.63 * 10 ^ -34 / sqrt(2) ( 9.11 * 10 ^-31) ( 1KeV) (1000eV / 1Kev) (1.6 * 10 ^ -19 J)

=

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