Electron and matter waves: WE NEED HELP

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SUMMARY

The discussion focuses on calculating the de Broglie wavelength for a 1.00 keV electron, photon, and neutron using the de Broglie wavelength formula, λ = h / p. Participants clarify the correct application of the kinetic energy formula, K = mv² / 2, and the momentum equation, p = mv. The mass of the electron is specified as 9.11 x 10^-31 kg, and the Planck constant is given as h = 6.63 x 10^-34 J·s. Key corrections include ensuring energy and mass are correctly placed within the square root for momentum calculations and proper unit conversions from Joules to electronvolts.

PREREQUISITES
  • Understanding of de Broglie wavelength calculations
  • Familiarity with kinetic energy and momentum equations
  • Knowledge of unit conversions between Joules and electronvolts
  • Basic understanding of particle physics concepts
NEXT STEPS
  • Learn about the implications of de Broglie wavelength in quantum mechanics
  • Study the relationship between energy, mass, and momentum in particle physics
  • Explore advanced topics in wave-particle duality
  • Investigate the behavior of photons and neutrons in quantum systems
USEFUL FOR

Students in physics, particularly those studying quantum mechanics, as well as educators and anyone interested in the calculations related to particle behavior and wave-particle duality.

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Electron and matter waves: WE NEED HELP!

Homework Statement


Calculate the de Broglie wavelength of (a) a 1.00Kev electron, (b) a 1.00Kev photon, and (c) a 1.00KeV neutron


Homework Equations


K = mv^2 / 2

p = mv

p = sqrt 2KM

m of electron is 9.11 * 10^-31 kg

1 ev = 1.6 * 10^-19 Joules

change in Lamda = h / p

h = 6.63 *^-34


The Attempt at a Solution




Is this correct. Here's what we tried.
)
change in lamda = 6.63 * 10 ^ -34 / sqrt(2) ( 9.11 * 10 ^-31) ( 1KeV) (1000eV / 1Kev) (1.6 * 10 ^ -19 J)

=



=
 
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Looks like you are setting things up okay. So what is the result of your calculation?

A couple of minor points:
The energy and mass belong inside the sqrt(), it's not clear if you are meaning to do that from what you wrote.
The "J" at the end of your expression should really be "J/eV" to do the units conversion properly.
 

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