Electron Capture by alpha particle -- Frequency of photon?

Click For Summary

Homework Help Overview

The problem involves an electron being captured by an alpha particle, specifically HE++, with a focus on calculating the frequency of the emitted photon following the capture. The context is rooted in atomic physics and energy conservation principles.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conservation of energy in the context of the problem, questioning whether to use total energy or potential energy in their calculations. There are attempts to clarify the relationship between kinetic energy, potential energy, and the energy of the emitted photon.

Discussion Status

Participants are actively engaging with the problem, raising questions about the assumptions made regarding energy states and the definitions of terms used in the calculations. Some guidance has been offered regarding the distinction between wavelength and frequency, and the appropriateness of the energy conservation approach.

Contextual Notes

There is confusion regarding the initial and final energy states of the electron, particularly concerning the concept of being unbound versus bound, and how this affects the calculation of the emitted photon's energy.

NucEngMajor
Messages
21
Reaction score
0

Homework Statement


Electron with KE = 50eV is captured by Alpha particle, ie. HE++. Calculate the frequency of the emitted photon.

Homework Equations


KE = m/2 v^2; E=hf, En = Z^2*-13.6eV/n^2

The Attempt at a Solution


Energy before = Energy after
50eV = 4*-13.6eV/1 + hf
f = 1200nm
 
Physics news on Phys.org
Something went wrong between the last two lines, the wavelength is way too long.
Also, 1200 nm is a length, not a frequency.

The electron doesn't have to go to the ground state directly, so you should at least say that you assume this.
 
Right. I solved for wavelength. 50 eV is a big KE so 1200nm seems reasonable? In general is the conservation of energy correct? I mean is it appropriate to put En + hf rather than Potential + hf?
 
The approach is right, just the result is wrong.
1200 nm is infrared light, with an energy of about 1 eV per photon. And 1200 nm is not a frequency, the problem statement asks for the frequency.
 
mfb said:
The approach is right, just the result is wrong.
1200 nm is infrared light, with an energy of about 1 eV per photon. And 1200 nm is not a frequency, the problem statement asks for the frequency.
Would you kindly explain why its T = En + hf and NOT T = U(r) + hf?
 
What is U(r)?
That looks like a very classical approach.
 
mfb said:
What is U(r)?
That looks like a very classical approach.
I'm just confused why the energy is En plus some additional hf. Initially it is unbound, n = infinity, right? After we drop to some E1 or En?
 
NucEngMajor said:
Initially it is unbound, n = infinity, right?
It is unbound with its energy above zero, so "n=infinity" is a problematic concept.

Initially it is unbound and has a positive energy, afterwards it is bound and has a negative energy. The energy of the photon is the difference of the two states. Subtracting a negative value from a positive will lead to an answer that is larger than the positive value. In other words, your photon will have an energy of more than 50 eV.
 

Similar threads

Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K