Why Does the Ni+ Ion Have an Electron Configuration of [Ar]3d9?

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The electron configuration of the Ni+ ion is [Ar]3d9, contrary to the initial assumption of [Ar]4s13d8. This discrepancy arises because, after ionization, one electron is promoted from the 4s to the 3d orbital, which is counterintuitive given that 4s is typically lower in energy. In transition metals, the shielding effect causes the 3d orbitals to have higher binding energies compared to the 4s orbital in heavier atoms. Consequently, the 3d orbitals become more stable, leading to the observed electron configuration. Understanding these nuances often requires quantum-mechanical calculations for clarity.
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Homework Statement


Which is the electron configuration of the Ni+ ion?

Homework Equations


Ni : [Ar]4s23d8

The Attempt at a Solution


Ni+: [Ar]4s13d8

Apparently this solution is wrong and should be Ni+: [Ar]3d9 but I do not know why. As far as I know 4s has less energy than 3d so, why does one electron promote from 4s to 3d after one ionization?
 
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This kind of thing is subtle. The only way to solve this kind of problems is by quantum-mechanical calculations, for example Cowan's old code.

In hydrogen, all orbitals with the same principle quantum number have (almost) the same energy. But when there are more electrons, the "circular" 3d orbitals are shielded much more than s-electrons, which makes that 4s is filled before 3d in transition metal atoms.

In heavier atoms, the 3d binding energies are larger than 4s, 4p, 4d, 4f.
 

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