Electron displacement between two parallel plates

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The discussion revolves around a physics problem involving an electron moving between two parallel plates with a given voltage, resulting in an upward deflection. The user has successfully calculated the electric field and acceleration but is struggling with part d, specifically how to relate the deflection to time without an initial velocity. A helpful response suggests using the kinematic equation for vertical motion, which incorporates deflection and acceleration. The user acknowledges the oversight and begins to apply the equation to find a solution. The exchange highlights the importance of kinematic principles in analyzing the motion of charged particles in electric fields.
SoundZombie
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The problem is attached, stuck on part d.

Homework Statement



Im given a problem with two horizontal and parallel plates 8cm long 3cm away from each other. An electron is moving through them with a velocity V_{0}. It is also given that the voltage across the plates is 20 Volts and the electron deflects upwards 1.2 cm.

Homework Equations



Ive done all the work for parts a, b, and c, which gave me a F_{electric} of 666.67 V/m or 666.67 N/C down, and an acceleration of 1.17 * 10^{14} m/s^{2} up.

The Attempt at a Solution



I have no idea how to even come at this. The only idea I had without being given an initial velocity in any direction is something with the deflection of 1.2 cm, but I don't know how to use that without knowing the amount of time the electron spends between the plates.

Thanks for ANY help.
 

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SoundZombie said:
The problem is attached, stuck on part d.

Homework Statement



Im given a problem with two horizontal and parallel plates 8cm long 3cm away from each other. An electron is moving through them with a velocity V_{0}. It is also given that the voltage across the plates is 20 Volts and the electron deflects upwards 1.2 cm.

Homework Equations



Ive done all the work for parts a, b, and c, which gave me a F_{electric} of 666.67 V/m or 666.67 N/C down, and an acceleration of 1.17 * 10^{14} m/s^{2} up.

The Attempt at a Solution



I have no idea how to even come at this. The only idea I had without being given an initial velocity in any direction is something with the deflection of 1.2 cm, but I don't know how to use that without knowing the amount of time the electron spends between the plates.

Thanks for ANY help.

Hello SoundZombie. Welcome to Physics Forums.

You've calculated an acceleration for the electron in the vertical direction, and you're given the vertical deflection that it experiences over its time between the plates. What can you make from that? What kinematic equation might apply?
 
gneill said:
Hello SoundZombie. Welcome to Physics Forums.

You've calculated an acceleration for the electron in the vertical direction, and you're given the vertical deflection that it experiences over its time between the plates. What can you make from that? What kinematic equation might apply?

I knew I was overlooking something small. haha

d_{y}=v_{0y}t+1/2a_{y}t^{2} which will end up being 1.2cm=(0)t+(1/2)(1.17*10^{14}m/s^{2})t

Im still having a little trouble remembering all of these because I took Physics 1 about 4 or 5 years ago, and I am just taking Physics 2 now. I am trying to re-learn everything at once. Thanks for the quick reply. Youre a life-saver!
 
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