Electron displacement between two parallel plates

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SUMMARY

The discussion centers on the analysis of an electron's motion between two parallel plates, specifically addressing the vertical deflection of 1.2 cm due to an electric field of 666.67 N/C. The problem involves calculating the time the electron spends between the plates, given its acceleration of 1.17 x 1014 m/s2 and the kinematic equation dy = v0yt + 1/2ayt2. The user seeks assistance in applying this equation to find the time variable, which is crucial for solving part d of the homework problem.

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  • Understanding of kinematic equations in physics
  • Knowledge of electric fields and forces (F = ma)
  • Familiarity with basic concepts of electron motion in electric fields
  • Ability to manipulate equations involving acceleration and displacement
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  • Review kinematic equations, particularly dy = v0yt + 1/2ayt2
  • Study the relationship between electric fields and forces on charged particles
  • Explore the concept of time of flight for particles in uniform acceleration
  • Investigate the effects of voltage on electron trajectories in parallel plate configurations
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Students studying introductory physics, particularly those focusing on electromagnetism and kinematics, as well as educators looking for practical examples of electron motion in electric fields.

SoundZombie
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The problem is attached, stuck on part d.

Homework Statement



Im given a problem with two horizontal and parallel plates 8cm long 3cm away from each other. An electron is moving through them with a velocity V[itex]_{0}[/itex]. It is also given that the voltage across the plates is 20 Volts and the electron deflects upwards 1.2 cm.

Homework Equations



Ive done all the work for parts a, b, and c, which gave me a F[itex]_{electric}[/itex] of 666.67 V/m or 666.67 N/C down, and an acceleration of 1.17 * 10[itex]^{14}[/itex] m/s[itex]^{2}[/itex] up.

The Attempt at a Solution



I have no idea how to even come at this. The only idea I had without being given an initial velocity in any direction is something with the deflection of 1.2 cm, but I don't know how to use that without knowing the amount of time the electron spends between the plates.

Thanks for ANY help.
 

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SoundZombie said:
The problem is attached, stuck on part d.

Homework Statement



Im given a problem with two horizontal and parallel plates 8cm long 3cm away from each other. An electron is moving through them with a velocity V[itex]_{0}[/itex]. It is also given that the voltage across the plates is 20 Volts and the electron deflects upwards 1.2 cm.

Homework Equations



Ive done all the work for parts a, b, and c, which gave me a F[itex]_{electric}[/itex] of 666.67 V/m or 666.67 N/C down, and an acceleration of 1.17 * 10[itex]^{14}[/itex] m/s[itex]^{2}[/itex] up.

The Attempt at a Solution



I have no idea how to even come at this. The only idea I had without being given an initial velocity in any direction is something with the deflection of 1.2 cm, but I don't know how to use that without knowing the amount of time the electron spends between the plates.

Thanks for ANY help.

Hello SoundZombie. Welcome to Physics Forums.

You've calculated an acceleration for the electron in the vertical direction, and you're given the vertical deflection that it experiences over its time between the plates. What can you make from that? What kinematic equation might apply?
 
gneill said:
Hello SoundZombie. Welcome to Physics Forums.

You've calculated an acceleration for the electron in the vertical direction, and you're given the vertical deflection that it experiences over its time between the plates. What can you make from that? What kinematic equation might apply?

I knew I was overlooking something small. haha

d[itex]_{y}[/itex]=v[itex]_{0y}[/itex]t+1/2a[itex]_{y}[/itex]t[itex]^{2}[/itex] which will end up being 1.2cm=(0)t+(1/2)(1.17*10[itex]^{14}[/itex]m/s[itex]^{2}[/itex])t

Im still having a little trouble remembering all of these because I took Physics 1 about 4 or 5 years ago, and I am just taking Physics 2 now. I am trying to re-learn everything at once. Thanks for the quick reply. Youre a life-saver!
 
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