Electron in a box - wavelength of photon

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SUMMARY

An electron trapped in a one-dimensional box measuring 526 nm transitions from the n=2 to n=7 energy level after absorbing a photon. The energy difference between these levels is calculated using the formula E_n = (n²h²)/(8mL²), leading to a wavelength of the absorbed photon. The least and most energetic photons emitted during transitions to the ground state (n=1) can be determined using the same energy formula. The calculations confirm that the wavelength of 0.020224 m is valid, considering the box's dimensions relative to the Bohr radius.

PREREQUISITES
  • Quantum mechanics principles, specifically energy levels in quantum systems
  • Understanding of the particle in a box model
  • Familiarity with the equations E_n = (n²h²)/(8mL²) and E = hv
  • Knowledge of photon wavelength calculations using λ = c/v
NEXT STEPS
  • Explore the particle in a box model in quantum mechanics
  • Study the implications of energy level transitions in quantum systems
  • Learn about the Bohr model and its application to electron transitions
  • Investigate photon emission and absorption processes in quantum mechanics
USEFUL FOR

Students studying quantum mechanics, physics educators, and anyone interested in the behavior of electrons in confined systems.

yango_17
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Homework Statement


a) An electron is trapped in a one-dimensional box that is 526 nm wide. Initially, it is in the n=2 energy level, but after a photon is absorbed the electron is in the n=7 energy level. What is the wavelength of absorbed photon?
b) Eventually, the electron ends up in the ground state. As it does so, one or more photons are emitted during those transitions. Find the wavelength of the least energetic and most energetic photons that might be emitted during all the possible transitions to the ground state.

Homework Equations


##E_{n}=\frac{n^{2}h^{2}}{8mL^{2}} ##
##\lambda =\frac{c}{v} ##
##E=hv ##

The Attempt at a Solution


How I attempted to solve part a) was to find the difference in energy between the n=7 and n=2 energy levels(basically take just do ## E_{7}-E_{2} ## using the first formula, and then use that energy and relate is to wavelength using the ##E=hv ## and the ##\lambda =\frac{c}{v} ## equations. Solving for wavelength, I obtained a value of 0.020224 m, which seems much too large. The same problem occurred when I attempted to solve part b), in which I designated the ##E_{7} ## to ##E_{1} ## the most energetic photon and the ##E_{2} ## to ##E_{1} ## the least energetic photon. Any help on this problem would be much appreciated, as its kept me tied up for quite a bit. Thanks!
 
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yango_17 said:
I obtained a value of 0.020224 m
When you compare the length of the box with the Bohr radius, the value you got there actually makes sense - the Bohr radius is more than two orders of magnitude smaller than the box's length.
 
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Your number appears correct. 526 nm is a huge box for an electron!
 
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Thanks!
 

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