Electron in constant magnetic field - classical vs quantum

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SUMMARY

The discussion centers on the behavior of an electron in a constant magnetic field, contrasting classical mechanics with quantum mechanics. In classical terms, the electron follows circular orbits dictated by the Lorentz force, leading to a continuous spectrum of energies. However, quantum mechanics introduces Landau levels, resulting in quantized energy states and wave functions that lack circular symmetry. The discussion highlights the importance of gauge choice in quantum mechanics, which can break symmetries, and introduces coherent states as a way to approximate classical behavior in quantum systems.

PREREQUISITES
  • Understanding of classical mechanics, specifically Lorentz force and circular motion.
  • Familiarity with quantum mechanics concepts, including wave functions and eigenstates.
  • Knowledge of Landau levels and their significance in quantum systems.
  • Basic grasp of gauge theory and its implications in quantum mechanics.
NEXT STEPS
  • Study the derivation and implications of Landau levels in quantum mechanics.
  • Explore the concept of coherent states and their applications in quantum harmonic oscillators.
  • Investigate gauge choices in quantum mechanics and their effects on symmetry properties.
  • Review S.M. Girvin's notes on quantum Hall effects and coherent states for deeper insights.
USEFUL FOR

Physicists, students of quantum mechanics, and anyone interested in the interplay between classical and quantum descriptions of particle dynamics in magnetic fields.

grelade
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Hi,

Movement of an electron in constant magnetic field, according to semiclassical QM, give rise to Landau levels - a quantization of energy. Everything would be fine but i find it difficult to reconcile these findings with classical point of view in which Lorentz force is acting on moving electron.
So, classically an electron will be moving in circular orbits according to condition:
[tex]m v^2 / r = evB[/tex]
We get continuous spectrum of circular orbits each with different energy E.

However when we're considering the same situation in QM (B field in z direction) we get a wave function of the electron like this (according to wikipedia and my own calculations):
[tex]\Psi (x,y) = e^{-i k_x x} H_n(\frac{y-x_0^2 k_x}{x_0}) e^{-(\frac{y-x_0^2 k_x}{\sqrt{2} x_0})^2}[/tex]
,where [tex]x_0=\sqrt{\hbar/eB}[/tex].

This solution is manifestly not circular-symmetric. Which it should be according to classical point of view. So plotting [tex]|\Psi|^2[/tex] don't seems to me like having any resemblance to classical motion at all and i don't have any idea why?
 
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Well, in general, the quantum mechanical eigenfunctions do not correspond to classical orbits. These eigenfunctions of the Hamiltonian form a basis of the Hilbert space -- which is one reason why we work with them -- but when we take the classical limit we usually do not find that these eigenfunctions turn into classical states. One reason you pointed out -- more or less. The eigenfunctions do not always posses the symmetries of the classical action (in this case these wavefunctions break rotational symmetry). In this case the origin of this "missing" symmetry is the fact that one has to make a choice of gauge in order to solve for the eigenfunctions. Choosing a gauge will in general break one or more symmetries (you can work in the symmetric gauge which is rotationally symmetric, but then you will lose translational symmetry).

We can, however, construct an wavefunction which is "as classical as possible". These wavefunctions are called coherent states. These states localize the particle as much as possible in both coordinate and momentum space. They are constructed as some linear combination of all the eigenstates. If you want to know what these coherent states exactly look like in the QHE you should look up the notes by S.M Girvin.

One thing I should add is that these eigenfunctions in some sense correspond to a whole collection of classical orbits with a radius of roughly the magnetic length.
 

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