Electron-Proton Relative Speed: Solving for 0.9c and -0.0994c

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najisalem2009
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Homework Statement


A laboratory experiment shoots an electron to the left at 0.9c. What is the electrons speed relative to a proton that is moving to the right at 0.9c?

I have no idea how to attempt this problem i know the answer is -.0994c but I am not sure how to get this answer?
 
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So i found the equation Its s= (v+u)/1+(vu/c²)

s=(0.9c+0.9c)/1+(0.9c)(0.9c)/(2.98*10⁸)²
i get s=.18c but the answer is -0.994c
 
Question: Why did you leave "0.9c" as it was, but then expressed "c" later as 2.98*10^8 m/s?

(This is where your problem resides.)
 
najisalem2009 said:
So i found the equation Its s= (v+u)/1+(vu/c²)

s=(0.9c+0.9c)/1+(0.9c)(0.9c)/(2.98*10⁸)²
i get s=.18c
It's wrong. That must be s=(0.9c+0.9c)/(1+0.81)=1.8c/1.81=0.994c
 
oh ok thanks a lot guys for clearing that up for me