Electron velocity and impact ionization?

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SUMMARY

The discussion centers on the conditions necessary for impact ionization of hydrogen gas by free electrons. It establishes that a potential of 13.6 volts applied to a metal plate can facilitate this process if the plate is positively biased relative to the electron source. The key factor is ensuring that the gas density is low enough to allow electrons to gain sufficient energy (13.6 eV) between collisions with neutral hydrogen atoms. This confirms that under the right conditions, impact ionization can occur in hydrogen gas.

PREREQUISITES
  • Understanding of ionization energy, specifically for hydrogen at 13.6 eV.
  • Knowledge of electron dynamics in electric fields.
  • Familiarity with concepts of gas density and mean free path.
  • Basic principles of cathode and anode behavior in electrical circuits.
NEXT STEPS
  • Research the effects of varying gas densities on electron collision rates.
  • Study the principles of impact ionization in different gases.
  • Explore the applications of ionization in gas discharge tubes.
  • Learn about the design and function of cathode-ray tubes (CRTs) and their ionization processes.
USEFUL FOR

Physicists, electrical engineers, and researchers in plasma physics who are interested in the mechanisms of ionization and electron behavior in gaseous environments.

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Hydrogen has an ionization energy of 13.6eV.

If 1eV is defined as the velocity of an electron produced by a potential of one volt.

Does this mean that a free electron contained in a hydrogen gas could cause impact ionization if a potential of 13.6 Volts were applied to a metal plate within the container holding the hydrogen gas?
 
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Hello HMS-
If a plate (let's call it anode) were biased by more than 13.6 volts positive relative to the electron source (call it cathode), and if the gas density were low enough (mean free path high enough) for the electrons from the cathode to gain 13.6 eV between collisions with the neutral hydrogen atoms or molecules, then you could get ionization.
Bob S
 

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