- #1
angelabean
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A beam of ions is deflected by the electric field between two plates 5cm apart with a p.d. pf 500 volts. It is found that this deflection is restored by a magnetic field of o.2T so that the ions continue in a straight line.
What is their velocity (ions) ?
So far I am thinking:
upward force, F=qE E=v/d, 500V/ 5exp-2m = 1exp4 Vm^-1
Downward force F=mv^2/ r = Bev
F= mv^2/r^2
I have some idea of what I need to do but some clarification would be great.
What is their velocity (ions) ?
So far I am thinking:
upward force, F=qE E=v/d, 500V/ 5exp-2m = 1exp4 Vm^-1
Downward force F=mv^2/ r = Bev
F= mv^2/r^2
I have some idea of what I need to do but some clarification would be great.