Magnetic field on rotating electron.

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Homework Help Overview

The discussion revolves around the magnetic field generated by a rotating electron around a proton, with specific parameters provided for velocity and diameter. Additionally, a new problem regarding the magnetic field at the center of a current-carrying wire loop is introduced.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to relate centripetal and magnetic forces to find the magnetic field, using equations for both forces. Some participants question the calculations and seek clarification on the results.

Discussion Status

The discussion includes attempts to calculate the magnetic field for the rotating electron problem, with one participant providing a numerical result. However, there is a lack of detailed exploration of the reasoning behind the calculations. A new problem is introduced, indicating a shift in focus, but it remains unclear if there is a consensus on the initial problem.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the depth of discussion on the initial problem. The introduction of a new problem suggests a potential transition in the topic being explored.

erhyde
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Homework Statement

an electron is rotating around a proton with a velocity of 2*10^6 m/s on circular path of diameter 5*10^-11 m. what is the magnetic field (B) ?
the centripetal force on the electron and the magnetic force should be equal and mv^2/r = Bqv or
B= mv/qr.

Homework Equations


centripetal force F=mv^2/r
magnetic force = Bqv.
 
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B=4.55*10^5 t
 
wzy7178 said:
B=4.55*10^5 t
[STRIKE]can you explain a bit more?[/STRIKE]

nvm found the answer.
 
Last edited:

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