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Magnetic field on rotating electron.

  1. Feb 5, 2014 #1
    1. The problem statement, all variables and given/known data


    an electron is rotating around a proton with a velocity of 2*10^6 m/s on circular path of diameter 5*10^-11 m. what is the magnetic field (B) ?



    the centripetal force on the electron and the magnetic force should be equal and mv^2/r = Bqv or
    B= mv/qr.


    2. Relevant equations
    centripetal force F=mv^2/r
    magnetic force = Bqv.
     
  2. jcsd
  3. Feb 5, 2014 #2
    B=4.55*10^5 t
     
  4. Feb 5, 2014 #3
    [STRIKE]can you explain a bit more?[/STRIKE]

    nvm found the answer.
     
    Last edited: Feb 5, 2014
  5. Feb 5, 2014 #4
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